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Unregistered guest
Posted From:
Posted on Tuesday, August 22, 2006 - 12:51 pm:   

help, any help on a solution to this one. been trying to win it for hours now! thanks for any help!

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paul forsdick (Pondpaul)
Master Solitaire Player
Username: Pondpaul

Post Number: 362
Registered: 10-2003
Posted on Wednesday, August 23, 2006 - 9:54 am:   

Hi Jennifer
this is up to where the 4th ace comes out

ah out, 6h up, ks up,4c up ,6s up ,jh-qc,2d-3s, 4c-5d, jh up,qc-kd,jh-qc,4c-5h, 9h up 10c -jd, 5d to space, 9h-10c. 5d up, 9h to space, 10c-jh, ks to space, 3c up, 8c-9h, qh-ks, 8d-9c, 6s to space, jd up ac out, 5d-6s, 6d up, 2c out,3c out,4c out,8d up,9c-10h, 4s-5d,8d-9c,4s-5h, 2d up, 3s-4d, qd-kc, 2d-3s, 2s up, ad out, 2d out qh to space, qd-ks,qh-kc,5d to space, 4s-5d, 3h-4s, 2s-3h ,3s up , 4d-5s,as out

regards Paul
Danny A. Jones
Unregistered guest
Posted From:
Posted on Wednesday, August 23, 2006 - 10:16 am:   

Here's a suggestion that should prove helpful. Carefully empth columns 8 & 6 while building a long chain on column 4. You will probably need to fill all four free cells initially. Be careful not to leave them full for too long. You should be able to empty them when the KS can head column 8.

If you want a full solution, then look below for one from FreeCell Pro. It's not an optimal solution, but it's pretty good. I have a reference to the notation in the FreeCell #817 thread (I think). Basically, 1-8 are columns, a-d are free cells, and h is a home cell.

#32408 Attempt: 1 NumFcs=4 (FCPro - Solved)
7h 8a 82 8b 4c 84 6d c4 8c 84
a8 6a 68 c4 6c b6 16 26 16 13
18 7b 74 c6 1c 17 14 d1 31 3d
bh 37 3b 34 24 27 24 21 6h 4h
bh 1b 1h 6h 51 56 ch 43 4h 4b
46 4c 42 4d 7h 7h 6h bh 7h 7h
3h 5h

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